Numbers in a matrix - HackerEarth Solution

t = input()
t = t.split(' ')
count = 0
d = []
for i in range(int(t[0])):
    s = []
    for j in range(int(t[1])):
        s.append(0)
    d.append(s)
s=0
for i in range(int(t[2])):
    c = input()
    c = c.split(' ')
    if int(c[0]) == 1:
        if d[int(c[1]) - 1][int(c[2]) - 1] == 0:
            d[int(c[1]) - 1][int(c[2]) - 1] = 1
        else:
            d[int(c[1]) - 1][int(c[2]) - 1] = 0
    elif int(c[0]) == 2:
        s+=1

if s%2==0:
    for i in range(len(d)):
        for j in range(len(d[i])):
            if d[i][j] == 1:
                count += 1
            else:
                continue
else:
    for i in range(len(d)):
        for j in range(len(d[i])):
            if d[i][j] == 0:
                count += 1
            else:
                continue
print(count)